4x+21=-(1/3)^x+4+6

Solution for 4x+21=-(1/3)^x+4+6 equation:

4x+21=-(1/3)^x+4+6

We move all terms to the left:

4x+21-(-(1/3)^x+4+6)=0


Domain of the equation: 3)^x+4+6)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

4x-(-(+1/3)^x+4+6)+21=0

We multiply all the terms by the denominator


4x*3)^x+4+6)-(-(+21*3)^x+4+6)+1=0

We add all the numbers together, and all the variables

4x*3)^x+4+6)-(-63^x+4+6)+1=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$